Question

I have this code:

Words = ['python','candy', 'banana', 'chicken', 'pizza', 'calculus',
     'cheeseburger', 'binder', 'computer', 'pencil', 'school'
     'artist', 'soccer', 'tennis', 'basketball', 'panda',
     'zebra', 'horse', 'cereal', 'alphabet', 'understand']

number = raw_input('Enter a 1 through 20: ')
x = list()
find = list(Words[int(number)-1])
notherword = list(Words[int(number)-1])
l = list(len(find)*'_')
print 'Your word is', len(find)*'_ '
playing = True
while playing:
    letter = raw_input('Please pick a letter ')
    if letter in find:
        a = find.index(str(letter))
        l[int(a)] = letter
        q = (' ')
        j = q.join(l)
        print j
        find[a] = ('_')
        if l == notherword:
            print 'You win!!!'
            playing = False
    else:
        print 'Strike ' +str(len(x)+1) +str('.') +str(' Not a letter in the word')
        x.append(letter)
        if len(x) > 4:
            print 'Game Over x('
            playing = False

This is a hangman game. You first pick a number then that number corresponds with the word and starts a game of hangman. But when i do the word banana it only finds the first a and does not find the other a’s. How do I code so that it can find multiple instances at the same time so that it runs through fine??

Edited with newer code

Answer 1

You should replace this

if letter in find:
    a = find.index(str(letter))
    l[int(a)] = letter

with this

letter_in_word = False
for a,c in enumerate(find):
    if c == letter:
        l[a] = letter
        letter_in_word = True
if letter_in_word:
    ...
else:
    ...