Question

I have this command:

find reports/ -type f -mtime +90 -regex ".*\.\(csv\|sql\|txt\|xls\|zip\)"

And I need to beef it up so the part before the file extensions matches a YYYY/MM/DD pattern, like so:

reports/2010/10/10/23.txt
reports/2010/10/10/23.xls
reports/2010/10/10/26.csv
reports/2010/10/10/26.sql
reports/2010/10/10/26.txt
reports/2010/10/10/26.xls
reports/2010/10/10/27.csv

But I’m failing to get any permutation of \d and parens escaping to work.

UPDATE: here’s what worked for me based on the accepted answer below:

find reports/ -type f -mtime +90 -regex "reports/201[01]/\([1-9]\|1[012]\)/\([1-9]\|[12][0-9]\|3[01]\)/.*\.\(csv\|sql\|txt\|xls\|zip\)"

Answer 1

This is what I have used in the past:

Year: (19|20)[0-9][0-9]
Month:  0[1-9]|1[012]
Day: (0[1-9]|[12][0-9]|3[01])

You can put these together in your regex. You will, ofcourse, have to escape the brackets and pipes.