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Home/ Questions/Q 6590613
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:19:19+00:00 2026-05-25T17:19:19+00:00

I have this cool little snippet that I found, which adds a shadow to

  • 0

I have this cool little snippet that I found, which adds a shadow to an image. (using imageMagick, i think..)

  image-shadow () {
  out=${1%.*}-shadow.${1#*.}
  in=$1
  echo "Converted file : $out"
  if [ ! -z $2 ] ; then 
    convert $in -frame $2 $out
    in=$out
  fi
  convert $in \( +clone -background black -shadow 60x5+3+3 \) \
    +swap -background transparent -layers merge +repage $out
  }

We use:

image-shadow test.png 0x0

to add 0x0 border, and 3×3 shadow, as defined inside the function…

Now, I have *-hd.png images, and *.png images .. And would like to add 3×3 shadows to the *.png and 6×6 to the *-hd.png (obviously, retina graphics..)

1- How can I compare the the image name, and decide

2- How can I pass the shadow size

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:19:19+00:00Added an answer on May 25, 2026 at 5:19 pm

    For 1.: Use find, it is really the Swiss army knife for such jobs:

    find '(' -name '*.png' -and -not -name '*-hd.png' ')' -exec image-shadow '{}' 0x0 ';'
    

    Of course, you’ll have to save your function as a single shell file instead of a shell function, but this is desirable for code reuse anyway.

    For 2.: Use another command line argument, which is referenced in the function as $3.

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