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Home/ Questions/Q 5850081
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T13:05:27+00:00 2026-05-22T13:05:27+00:00

I have this custom primary key in a model: class Personal(models.Model): name = models.CharField(max_length=20,primary_key=True)

  • 0

I have this custom primary key in a model:

class Personal(models.Model):
    name = models.CharField(max_length=20,primary_key=True)
    email = models.EmailField(blank=True,null=True)

Now the thing i m not getting is, how can i create my view so that no duplicate record is entered? I searched this over online, but could find any technique to get the view created.

here is the code for views

def uregister(request):
    errors = []
    if request.method == 'POST':
        if not request.POST.get('txtName', ''):
            errors.append('Enter a Name.')
        if not errors:
            n = request.POST['txtName']
            e = request.POST['txtEmail']
            try:
                per_job = Personal(name=n, email=e)
                per_job.save()
            except IntegrityError:
                return render_to_response('gharnivas/register.html', {'exists': true}, context_instance=RequestContext(request))

            return HttpResponseRedirect('/')
        else:
            return render_to_response('register.html', {'errors': errors}, context_instance=RequestContext(request))

How can i tel the user that, the name already exists?

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  1. Editorial Team
    Editorial Team
    2026-05-22T13:05:28+00:00Added an answer on May 22, 2026 at 1:05 pm

    Catch the inevitable exception upon saving, and tell them.

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