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Home/ Questions/Q 3855658
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T17:48:35+00:00 2026-05-19T17:48:35+00:00

I have this data: inventory = { HAMMER: (10,100), SCREW: (1, 1000), NAIL: (1,

  • 0

I have this data:

inventory = { HAMMER: (10,100),
              SCREW: (1, 1000),
              NAIL: (1, 1000),
              SCREWDRIVER: (8, 100),
              DRILL: (50, 20),
              WORKBENCH: (150, 5),
              HANDSAW: (15, 50),
              CHAINSAW: (80, 30)
            }

Which I have written the following function:

def get_items(cheapness):
    """ Return a list of (item, (price, count)) tuples that are the given
    cheapness. Note that the second element of the tuple is another tuple. """

    if cheapness == 'CHEAP':
        return [(key, value) for (key,value) in inventory.items() if value in ((cost,quantity) for (cost, quantity) in inventory.values() if cost < 20)]
    elif cheapness == 'MODERATE':
        return [(key, value) for (key,value) in inventory.items() if value in ((cost,quantity) for (cost, quantity) in inventory.values() if 20 < cost < 100)]
    elif cheapness == 'EXPENSIVE':
        return [(key, value) for (key,value) in inventory.items() if value in ((cost,quantity) for (cost, quantity) in inventory.values() if cost > 100)]

My problem is when I do a print type(get_items(CHEAP)), I get <type 'NoneType'>. How do I return the results as a list?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T17:48:36+00:00Added an answer on May 19, 2026 at 5:48 pm

    Say what you mean:

    def get_items(cheapness):
        """ Return a list of (item, (price, count)) tuples that are the given
        cheapness. Note that the second element of the tuple is another tuple. """
    
        if cheapness == 'CHEAP':
            return [(item, (price,count)) for (item, (price,count)) in inventory.items() if price < 20]
        elif cheapness == 'MODERATE':
            return [(item, (price,count)) for (item, (price,count)) in inventory.items() if price > 20 and price < 100]
        elif cheapness == 'EXPENSIVE':
            return [(item, (price,count)) for (item, (price,count)) in inventory.items() if price > 100]
    
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