I have this equation:
R= 2*(-I dot N)*N + I
Can I simply type (-I) or something similar, or do I have to multiply I by -1?
I have this equation: R= 2*(-I dot N)*N + I Can I simply type
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I have this equation:
R= 2*(-I dot N)*N + I
Can I simply type (-I) or something similar, or do I have to multiply I by -1?
C++ has a unary minus operator that performs negation.
This negates
x, just like0 - xor-1 * xwould negatex. Note that the-in-1 * xis also the unary minus operator.