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Home/ Questions/Q 8599325
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T01:22:25+00:00 2026-06-12T01:22:25+00:00

I have this following loop for a code (that computes the histograms). I am

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I have this following loop for a code (that computes the histograms). I am writing in Matlab. As I am new to Matlab I don’t know of any faster methods to do this. I am currently writing

for i=1:size(b)
    a(b(i)) = a(b(i)) + 1;
end

Are there any faster methods to do this, preferably those which do not require the for loop?

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  1. Editorial Team
    Editorial Team
    2026-06-12T01:22:27+00:00Added an answer on June 12, 2026 at 1:22 am

    You can simply vectorize it by a(b) = a(b) + 1. Check the following:

    >> a = [1 2 3 4];
    >> b = [2 4]; %# indices to modify. Be sure that they are in bounds.
    >> a(b) = a(b) + 1
    
    a =
    
         1     3     3     5
    

    If you use some indices multiple times, then accumarray will help as follows:

    >> a = [1 2 3 4];
    >> b = [2 4 2];
    >> a = accumarray([1:numel(a) b].',[a ones(size(b))])'
    
    a =
    
         1     4     3     5
    

    Alternatively, you can use:

    >> a = [1 2 3 4];
    >> b = [2 4 2];
    >> b = accumarray(b.',ones(size(b)));
    >> a(nzIndex) = a(nzIndex) + b(nzIndex)'
    
    a =
    
         1     4     3     5
    

    See this nice answer here for further details.

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