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Home/ Questions/Q 9253677
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:16:45+00:00 2026-06-18T11:16:45+00:00

I have this function: $(function ($) { … }); var getNotifyBar = $(.NotifyBar); function

  • 0

I have this function:

$(function ($) {
...
});

var getNotifyBar = $(".NotifyBar");
function showNotify(text) {
    getNotifyBar.hide().find(".text").html(text).end().slideDown();
}

And when I use function showNotify(text) nothing happens. But when I put it in the JavaScript console (of the browser) it works.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:16:46+00:00Added an answer on June 18, 2026 at 11:16 am

    More than likely this is running before all the elements with class NotifyBar are rendered

    var getNotifyBar = $(".NotifyBar");
    

    Which means that it is empty when you try to use it later. you should do this instead:

    var getNotifyBar;
    $(function ($) {
     getNotifyBar = $(".NotifyBar");
    });
    

    Now it should be properly loaded. Next, you need to remember that getNotifyBar is a reference to a jQuery object already loaded from a selector. As such, you do not need to wrap it in $(). You should make this change:

    function showNotify(text) {
     getNotifyBar.hide().find(".text").html(text).end().slideDown();
    }
    
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