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Home/ Questions/Q 742693
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:46:38+00:00 2026-05-14T08:46:38+00:00

I have this function: if (is_dir($dir)) { //are we able to open it? if

  • 0

I have this function:

if (is_dir($dir)) {
        //are we able to open it?
        if ($dh = opendir($dir)) {
            //Let's cycle
            while (($subdir = readdir($dh)) !== false) {
                if ($subdir != "." && $subdir != "..") {

                    echo $subdir;

                }
        }
}

This returns:

directory1 , directory2, directory3 etc.. etc..

Hoever if I do this:

    if (is_dir($dir)) {
        //are we able to open it?
        if ($dh = opendir($dir)) {
            //Let's cycle
            while (($subdir = readdir($dh)) !== false) {
                if ($subdir != "." && $subdir != "..") {

                    if (is_dir($subdir)) { 
                       echo $subdir;
                    }

                }
        }
}

It doesn’t print nothing!

Why does this happens?
I’m running the script withing windows and XAMPP for testing purposes. The directory does in fact contain directories.

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:46:38+00:00Added an answer on May 14, 2026 at 8:46 am

    is_dir($dir . '/' . $subdir)

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