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Home/ Questions/Q 8719159
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:43:32+00:00 2026-06-13T06:43:32+00:00

I have this function. My pygame’s text to rectangle converter. def text_to_rect(text, name=’default’): try:

  • 0

I have this function. My pygame’s text to rectangle converter.

def text_to_rect(text, name='default'):
    try:
        font  = load.text_style[name]['font']
        aa    = load.text_style[name]['aa']
        color = load.text_style[name]['color']
    except NameError:
        font_path = pygame.font.get_default_font()
        font = pygame.font.Font(font_path, 24)
        aa = 1
        color = (0,0,0)
        if not name=='default':
            text = text+'(ERROR: Global load object not defined.)'
    except KeyError:
        font_path = pygame.font.get_default_font()
        font = pygame.font.Font(font_path, 24)
        aa = 1
        color = (0,0,0)
        if not name=='default':
            text = text+'(ERROR: '+name+' text style does not exist.)'
    return font.render(text,aa,color)

In two except blocks there are 4 lines of the same code. I want to run these 4 lines if any exception occurs, then rest to a specific exception.

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:43:33+00:00Added an answer on June 13, 2026 at 6:43 am

    You can actually combine exceptions into one statement:

    try:
        #code that you expect errors from
    
    except KeyError, NameError:
        #exception code
    
    except:
        #Of course, you can also do a naked except to catch all
        #exceptions,
        #But if you're forced to do this, you're probably
        #doing something wrong. This is bad coding style.
    

    EDIT
    For your case, if you want your code execution to depend on the error caught, do this:

    try:
        #Code to try
    except (KeyError, NameError) as e:
        #Code to execute in either case
        if isinstance(e, KeyError):
            #code to execute if error is KeyError
        else:
            #code to execute if error is NameError
    
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