Question

I have this function takes more than one char parameters.how to print each of them and add a ‘\n’ at the end of each char?

void printAndSave(char* msg,...)
{
     //printing single one.
    //printf("Log:%s\n",msg);
    //saveToLog(msg);

   //how to print all of them?

}

Answer 1

I think you will need to change the signature of printAndSave() to specify the number of char* arguments being passed. For example:

void printAndSave(const unsigned int arg_count, ...)
{
    unsigned int i;
    char* val;
    va_list vl;

    va_start(vl,arg_count);
    for (i=0;i<arg_count;i++)
    {
        val=va_arg(vl,char*);
        printf ("%s\n",val);
    }
    va_end(vl);
}