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Home/ Questions/Q 7566803
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T14:30:22+00:00 2026-05-30T14:30:22+00:00

I have this function to open a jQuery UI dialog: function pop_up(div, titulo) {

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I have this function to open a jQuery UI dialog:

function pop_up(div, titulo) {
  $("#" + div).dialog({
    autoOpen: false,
    show: "explode",
    hide: "explode",
    modal: true,
    minHeight: 550,
    height: "auto",
    width: "auto",
    title: titulo,
  });

  $("#" + div).dialog("open");

  return false;
}

which I call in the same hidden div:

pop_up('pop', 'my title');

Which works fine (I can open and close as many times as I want) but if I load some content dynamically in the #div I get this firebug error (in the next attempt to open a dialog)

$("#" + div).dialog is not a function
[Parar en este error]   

title: titulo

Basically

pop_up('pop', 'my title');   /* OK */

$('#pop').load('somefile.html',function(){
    pop_up('pop', 'some title');   /* CRASH */
});

will fire the error; any idea what am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T14:30:23+00:00Added an answer on May 30, 2026 at 2:30 pm

    In your example, you are calling pop_up() with an id of div. I’m not sure that is a good id value, but just the same in the next line of code you try to load ‘somefile.html’ into #pop which may have not been created yet. Then you try to create a new pop_up which is referencing the same object that is being loaded (#pop).

    Would this work?

    pop_up('div1', 'my title');
    $('#div1').load('somefile.html',function(){
        pop_up('pop', 'some title');
    });
    

    Here we use a dialog with an id of div1. Then we load ‘somefile.html’ into that dialog. Once that load is completed, we create a new pop_up called pop.

    Hope this helps!

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