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Home/ Questions/Q 3980100
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T05:15:02+00:00 2026-05-20T05:15:02+00:00

I have this function to sort a JavaScript array of objects based on a

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I have this function to sort a JavaScript array of objects based on a property:

// arr is the array of objects, prop is the property to sort by
var sort = function (prop, arr) {
    arr.sort(function (a, b) {
        if (a[prop] < b[prop]) {
            return -1;
        } else if (a[prop] > b[prop]) {
            return 1;
        } else {
            return 0;
        }
    });
};

It works with arrays like this:

sort('property', [
    {property:'1'},
    {property:'3'},
    {property:'2'},
    {property:'4'},
]);

But I want to be able to sort also by nested properties, for example something like:

sort('nestedobj.property', [
    {nestedobj:{property:'1'}},
    {nestedobj:{property:'3'}},
    {nestedobj:{property:'2'}},
    {nestedobj:{property:'4'}}
]);

However this doesn’t work because it is not possible to do something like object['nestedobj.property'], it should be object['nestedobj']['property'].

Do you know how could I solve this problem and make my function work with properties of nested objects?

Thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T05:15:03+00:00Added an answer on May 20, 2026 at 5:15 am

    You can split the prop on ., and iterate over the Array updating the a and b with the next nested property during each iteration.

    Example: http://jsfiddle.net/x8KD6/1/

    var sort = function (prop, arr) {
        prop = prop.split('.');
        var len = prop.length;
    
        arr.sort(function (a, b) {
            var i = 0;
            while( i < len ) { a = a[prop[i]]; b = b[prop[i]]; i++; }
            if (a < b) {
                return -1;
            } else if (a > b) {
                return 1;
            } else {
                return 0;
            }
        });
        return arr;
    };
    
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