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Home/ Questions/Q 8626793
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T08:07:05+00:00 2026-06-12T08:07:05+00:00

I have this function which takes the average user rating given to an item

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I have this function which takes the average user rating given to an item and converts it to a relevant class:

function get_user_rating_class($urate_ave){
    if($urate_ave==='0.0'){
        $user_rating_class='unrated_u';
    }else{
        $round_to = 0.5;
        $rounded = round($urate_ave / $round_to) * $round_to;
        $removedec = str_replace('.','',$rounded);
        if(strlen($removedec)<2){$removedec.'0';}
        $user_rating_class='rating_user_'+$removedec;
    }
    return $user_rating_class;
}

No when I put a value, say 3.0 into the function it should come out as rating_user_30 but instead it is coming out as rating_user_3, so there must be something wrong with this line:

if(strlen($removedec)<2){$removedec.'0';}

I thought it might be because It was treating the value $removedec as a number rather than a string so I tried adding this line just before it, but no change:

$removedec = strval($removedec);

Could someone tell me what I am doing wrong here.

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  1. Editorial Team
    Editorial Team
    2026-06-12T08:07:06+00:00Added an answer on June 12, 2026 at 8:07 am

    You should use .= instead of . to append a value to a string and set the variable to that value. The dot operator alone will append the value but not change the variable’s value.

    $removedec .= '0';
    
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