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Home/ Questions/Q 9158989
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T13:23:01+00:00 2026-06-17T13:23:01+00:00

I have this function which uses ajax, but this function doesn’t work. I tried

  • 0

I have this function which uses ajax, but this function doesn’t work. I tried a lot, but I’m not able to figure out where the problem is. I am trying to create an alert, when the user inserts a duplicate entry into the database using a check-box selection.

<script>    
    function func(e,eid,emprid) {
       if(document.getElementById(e).checked){
          var dataString = 'eid=' + eid + '&emprid='+emprid;
          $.ajax({
             type:"POST",
             url: "mylistcheck.php",
             data: dataString,
             success: function(result){
                if(result!='0') {
                   modal.open({content: "<span style=\"color:red\" ><h2>You have already selected  candidate </h2></span>"});
                   document.getElementById(e).checked=false;
                }
             }
          });
       } 
    }
</script>

mylistcheck.php looks like this:

<?php require_once("includes/session.php"); ?>
<?php require_once("includes/connection.php"); ?>
<?php require_once("includes/functions.php"); ?>
<?php
    $eid=$_POST['eid'];
    $emprid=$_POST['emprid'];

    $sqlchecklist="SELECT * FROM selected_candidate WHERE eid='{$eid}' AND rid='{$emprid}' ";
    $checklistres=mysql_query($sqlchecklist);
    $list_check=mysql_num_rows($checklistres);
    echo "numrows listcheck".$list_check;
    if($list_check>0) {
        echo "1";
    } else {
        echo "0";
    }
?>

The check-box code is like this:

echo "<td><input id=\"select_candi{$i}\" onclick=\"javascript:func(this.id,{$data_set['eid']},{$emprid})\" type=\"checkbox\" name=\"check_candi[]\" value=\"{$data_set['eid']},{$emprid}\"/></td>"; 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T13:23:03+00:00Added an answer on June 17, 2026 at 1:23 pm

    In your code you have

    echo "eid".$eid;
    $emprid=$_POST['emprid'];
    echo "rid".$emprid;
    

    Since you are already echoing the result your ajax functie will never be just ‘0’. Its always something like eid{value}rid{value}0 or eid{value}rid{value}1

    Also switch to mysqli or pdo for security reasons. Also check the values of $eid and $rid to match what you expect. Your code is vulnerable for SQL injection.

    In your script code you have onclick="javascript:func(...)". onclick is already a javascript function, so you dont need the javascript:

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