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Home/ Questions/Q 6922875
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:27:47+00:00 2026-05-27T10:27:47+00:00

I have this function which, when I click a button, another div will be

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I have this function which, when I click a button, another div will be shown, and another div will be hidden. The code works, but it’s sloppy. Is there any good ideas how to shorten the function down?

$(document).ready(function(){
    $("#page-1-button").click(function(){
        $("#page-2").css('display','inline');
        $("#page-1").css('display','none');
        $('html, body').animate({scrollTop:'0px'},300)
    });

    $("#page-2-button").click(function(){
        $("#page-3").css('display','inline');
        $("#page-2").css('display','none');
        $('html, body').animate({scrollTop:'0px'},300)
    });

    $("#page-2-button-back").click(function() {
        $("#page-1").css('display','inline');
        $("#page-2").css('display','none');
        $('html, body').animate({scrollTop:'0px'},300)
    });

    $("#page-3-button-back").click(function(){
        $("#page-2").css('display','inline');
        $("#page-3").css('display','none');
        $('html, body').animate({scrollTop:'0px'},300)
    })
});



<div id="page-1"> <input id="page-1-button" /> </div>
<div id="page-2"> <input id="page-2-button" /> <input id="page-2-button-back" /> </div>
<div id="page-3> <input id="page-3-button-back" /> </div>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:27:48+00:00Added an answer on May 27, 2026 at 10:27 am

    Depending on your HTML, you may want to look at manipulating elements in relation to the button:

    Not knowing your HTML structure, I’ll guess:

    $(".button").click(function(){
            $(this).closest('.page').show();
            $(this).next('.page').hide();
    ...etc...
    })
    

    This way the same code can work for all of the elements using class names and relative DOM positions, without needing to make a specific call for each ID.

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