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Home/ Questions/Q 8374337
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T14:54:05+00:00 2026-06-09T14:54:05+00:00

I have this getResult() with slight variation in Input parameter. one Mapvalue as string

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I have this getResult() with slight variation in Input parameter. one Mapvalue as string array for one and string for anor .

But I am seeing a error:
Wont overloading support generics?

public class App 
{

public void getResult(Map<String, String[]> map) {

}
public void getResult(Map<String, String> map) {

}

}

I am seeing this error:Method getResult(Map) has the same erasure getResult(Map) as another method in type App
I guess java is treating both as just Maps and so is this error.

what is best approach to mimic this behaviour?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-09T14:54:06+00:00Added an answer on June 9, 2026 at 2:54 pm

    One of the rules of overloading is that methods with type parameters cannot have the same signature after erasure. See the Java Language Specification, §8.4.8.3. The relevant text from the spec is:

    It is a compile-time error if a type declaration T has a member method m1 and there exists a method m2 declared in T or a supertype of T such that: . . . The signature of m1 or some method m1 overrides (directly or indirectly) has the same erasure as the signature of m2 or some method m2 overrides (directly or indirectly).

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