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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:35:41+00:00 2026-05-26T19:35:41+00:00

I have this hex value 93 which in decimal value should be 147. Since

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I have this hex value 93 which in decimal value should be 147. Since this number is less than 255, it is representable in a byte.

In java I did this

System.out.println((new Integer(1)).byteValue()); //prints 1
System.out.println((new Integer(147)).byteValue()); //prints -109!!! WHY?

What am I not understanding? with integer of 147 instead of printing 147 it prints -109…

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:35:42+00:00Added an answer on May 26, 2026 at 7:35 pm

    Because byte is in the range -128:127 (see here). When you call byteValue() you can’t get anything out of that range, so it overflows (and starts from the lowest value)

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