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Home/ Questions/Q 6359447
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:31:11+00:00 2026-05-24T23:31:11+00:00

I have this HTML structure <img width=25 height=25 src=/data/apple_logo.jpg alt=Chocolate /> <input class=cake_checkboxes style=vertical-align:

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I have this HTML structure

<img  width="25" height="25" src=/data/apple_logo.jpg alt=Chocolate />      
  <input class="cake_checkboxes" style="vertical-align: bottom;"  type="checkbox" name="option[232][]" value="23" id="option-value-23" />
  <label for="option-value-23"> Chocolate</label>
  <br />
<div style='display:none;' class="quantity">
......

If i do

$('.cake_checkboxes:first').next('div')

or

$('.cake_checkboxes:first').next('.quantity')

I get an empty value returned but if i do this

$('.cake_checkboxes:first').next().next().next()

I get the div i need …any ideas on what is wrong or if there is a way to traverse down like the jquery closest method traverses up

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:31:12+00:00Added an answer on May 24, 2026 at 11:31 pm

    next() only returns the next element in the DOM if it matches the selector, otherwise it returns and empty object. So the only thing you could search for using next() is the <label>. Use this instead:

    $('.cake_checkboxes:first').nextAll('.quantity').first()
    

    jQuery Docs: nextAll()

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