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Home/ Questions/Q 7512527
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T23:53:32+00:00 2026-05-29T23:53:32+00:00

I have this in an exercise with pointers: char *str = Hello; int count

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I have this in an exercise with pointers:

char *str = "Hello";
int count = 0;
int len = 5;
printf("%c\n", *(str + count));
printf("%c\n", *(str + len - count - 1));
*(str + count) = *(str + len - count - 1);

Both *(str + count) and *(str + len - count - 1) are valid values as the printfs attest (I get H and o). So why do I get a bus error when I run the above?

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  1. Editorial Team
    Editorial Team
    2026-05-29T23:53:33+00:00Added an answer on May 29, 2026 at 11:53 pm

    str points to a string literal which resides in memory where it is undefined behaviour to write to. Many times the compiler will put these string literals into memory with permissions that do not include write-permissions. This is why you’re crashing.

    Change it to this:

    char str[] = "Hello";
    

    This will create an array on the stack and initialise it with the C-string "Hello"; since it resides on the stack, you can freely modify it.

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