Question

I have this issue that I can’t seem to get my head around… Basically I have a form that the user inputs a

• start mile
• start yard
• end mile
• end yard

I am trying to query my SQL Server database using the values, that the user inputs… I can retrieve the information fine, but I just need help with the query.

The issue is the data is in the following format in the database:

 ID | mile | yard | gps lat | gps long | rotten | split | wheel_cut | broken | quality |
  1, 234, 2342,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  2, 234, 2954,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  3, 234, 2994,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  4, 235,   42,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  5, 235, 2842,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  6, 236,  242,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  7, 236, 2342,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  8, 237,  282,   35.23143, -123.32423, 1, 2, 1, 2, 2 
  9, 238, 2342,   35.23143, -123.32423, 1, 2, 1, 2, 2 
 10, 238, 4342,   35.23143, -123.32423, 1, 2, 1, 2, 2 
 11, 239,  742,   35.23143, -123.32423, 1, 2, 1, 2, 2 

I need to query both mile and yard at the same time, so for example the user types in:

• start mile = 234

• start yard = 2954

• end mile = 236

• end yard =2342

The query should output IDs 3, 4, 5, 6 and 7.

If I just query WHERE mile > 234 AND yard > 2954... It will ignore ID 4 because the yard is less than 2954.

SELECT   
    id, mile,  yard, gps_lat, gps_long, rotten, split, wheel_cut, broken, quality
FROM    
    database
WHERE 
    gps_lat IS NOT NULL 
    AND (???????)
ORDER BY 
    mile, yard.

Is there anyone that can help me with this query? Any advice would be welcomed!

I hope I explained the situation clearly enough….

Cheers,

Neil

Answer 1

this isn’t the best way, but you could try converting your mile data points into yards, then adding both datapoints, and then selecting between the start and stop yardage.

so for example:

declare @startmile int, @endmile int, @startyard int, @endyard int

set @startyard=@startyard+(@startmile*1760)
set @endyard=@endyard+(@endmile*1760)


select *
from dbo.Table_1
where yard+(mile*1760) between @startyard and @endyard

there’s probably a better way to write that, but i can’t think of it.