Question

I have this java code that, using apache jena api, queries the pizza ontology

    String queryStr =
"prefix pizza: <" + PIZZA_NS + "> "               +
"prefix rdfs: <" + RDFS.getURI() + "> "           +
"prefix owl: <" + OWL.getURI() + "> "             +
"select ?pizza where {?pizza a owl:Class ; "      +
"rdfs:subClassOf ?restriction. "                  +
"?restriction owl:onProperty pizza:hasTopping ;"  +
"owl:someValuesFrom pizza:PeperoniSausageTopping" +
"}";


Query query = QueryFactory.create(queryStr);
QueryExecution qe = QueryExecutionFactory.create(query, model);
ResultSet rs = qe.execSelect();


ArrayList rsList = (ArrayList)ResultSetFormatter.toList(rs);
for(int i=0;i<rsList.size();i++){
    out.println(rsList.get(i).toString());
}

It returns this:

( ?pizza = <http://www.co-ode.org/ontologies/pizza/pizza.owl#AmericanHot> )
( ?pizza = <http://www.co-ode.org/ontologies/pizza/pizza.owl#FourSeasons> )
( ?pizza = <http://www.co-ode.org/ontologies/pizza/pizza.owl#American> )

but I need only

AmericanHot

FourSeasons

American

How to obtain this result?

Answer 1

The SPARQL 1.1 function STRAFTER can help:

SELECT ?pizza (strafter(str(?pizza), "#") AS ?localName)
WHERE

but the client side solution is just as good and works with SPARQL 1.0.