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Home/ Questions/Q 9129507
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T07:45:51+00:00 2026-06-17T07:45:51+00:00

I have this JavaScript code: $(document).ready(function(){ $(‘#sel’).change(function(){ $.ajax({ type: POST, url: modules.php?name=TransProject_Management&file=index, data: &op=index_stat&stat=+$(this).val(),

  • 0

I have this JavaScript code:

$(document).ready(function(){ 
           $('#sel').change(function(){

        $.ajax({
                      type: "POST", 
                      url: "modules.php?name=TransProject_Management&file=index",
                      data: "&op=index_stat&stat="+$(this).val(),
                      cache: false,
                      success: function(data) {
                         //alert(data);
                         $("#ajax_results").html(data);
                     }
                  }); 

});
});

On status change i need to refresh a div without page reload. But it returns blank page. If i try alert the result on success, i get the response, also i checked with inspect element, its ok. The problem is that it returns blank page.

The file i’m working on, is the same( modules.php?name=TransProject_Management&file=index ) i called in ajax.

the html:

<body>
//...
<div id="ajax_results">
//.....
//somewhere here is the select option <select id="sel">......</select>
//.....
</div>
</body>

Any help, would be very appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T07:45:53+00:00Added an answer on June 17, 2026 at 7:45 am

    use the following code to return your response html:

    echo json_encode(array($your_response));
    

    Then in your javascript, you will need to reference the data as:

    success: function(data) {
        $("#ajax_results").html(data[0]);
    }
    

    since it is now an array.

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