Question

I have this Javascript code, which works as expected:

<div class="test"></div>

<script>
setTimeout(function(){$(".test").append("test1")},1000);
setTimeout(function(){$(".test").append("test2")},2000);
</script>
<script src="js/jquery.min.js"></script>

It shows “test1” first and then “test2” a second later, as such: “test1test2”, which is what I want.

When I try to do this in a FOR loop, like this:

var timeInterval = 1000;
for (var i = 0, l = 2; i < l; i++ ) {
    setTimeout(function(){$(".test").append("test" + i)},timeInterval);
    timeInterval += 1000;
}

Then I get “test2” first and then “test2” a second later, as such: “test2test2”, which is not what I want.

In fact, if l = 3, then I get “test3test3test3” instead of “test1test2test3”. Does anybody know how to solve this problem?

Answer 1

The var i is incremented to 2 when the setTimeout is executing the function and so it just prints the i value as 2 resulting in test2test2.

You should use a closure to use the instance of i which will print test1test.

DEMO: http://jsfiddle.net/mBBJn/1/

var timeInterval = 1000;
for (var i = 0, l = 2; i < l; i++) {
    (function(i) {
        setTimeout(function() {
            $(".test").append("test" + (i+1))
        }, timeInterval);
        timeInterval += 1000;
    })(i);
}

Edit: used function args.