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Home/ Questions/Q 8180847
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T00:19:47+00:00 2026-06-07T00:19:47+00:00

I have this Javascript/JQuery code: <script type=text/javascript src=http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js></script> <script type=text/javascript> name = $(#name).val(); alert(Name:

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I have this Javascript/JQuery code:

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

<script type="text/javascript">

    name = $("#name").val();

    alert("Name: " + name);

</script>

And this HTML:

<form name="report" action="send.php" method="post">

    <input type="text" name="name" id="name" value="Senna" />
    <input type="submit" value="Send" />

</form>

When the page loads i get “Name: undefined” instead of “Name: Senna”.

Can someone help me to get the expected result?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T00:19:49+00:00Added an answer on June 7, 2026 at 12:19 am

    While JavaScript provides the load event for executing code when a
    page is rendered, this event does not get triggered until all assets
    such as images have been completely received. In most cases, the
    script can be run as soon as the DOM hierarchy has been fully
    constructed. The handler passed to .ready() is guaranteed to be
    executed after the DOM is ready, so this is usually the best place to
    attach all other event handlers and run other jQuery code.

    You need to indicate to execute the function once the page has been loaded. Currently you are only defining it and not decalring when to execute it.

    $(document).ready(function(){
        name = $('#name').val();
        alert('Name: ' + name);
    });
    

    Or:

    $(function(){
        name = $('#name').val();
        alert('Name: ' + name);
    });
    
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