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Home/ Questions/Q 9116113
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T04:35:36+00:00 2026-06-17T04:35:36+00:00

I have this jQuery $(document).ready(function(){ $(‘#credit_btn, #checkout_btn’).click(function(){ $(#content_container .notice, #content_container .error).remove(); $(‘#loading’).show(); }); });

  • 0

I have this jQuery

$(document).ready(function(){
  $('#credit_btn, #checkout_btn').click(function(){
    $("#content_container .notice, #content_container .error").remove();
    $('#loading').show();
  });
});

The HTML

<div id="loading" style="display: none;">
  <img alt="spinner" border="0" src="/assets/spinner.gif">
</div>
<input class="bigbutton" data-disable-with="One Moment, Processing..." id="checkout_btn" name="commit" type="submit" value="Next Step: Checkout">

why is the spinning not showing up it shows up when i do

  $j('#credit_btn, #checkout_btn').click(function(){
    $j("#content_container .notice, #content_container .error").remove();
    $j('#loading').show();
    return false;
  });

what is happening here and is there anything I can do? Thanks in advance

UPDATE

I tested this jquery as well

  $('#credit_btn, #checkout_btn').click(function(e){
    e.preventDefault();
    $("#content_container .notice, #content_container .error").remove();
    $('#loading').show();
    $(this).closest("form").submit();
  });

the spinner doesnt come up again but it shows up when i remove the line $(this).closest("form").submit(); …I am confused…why does the form submit have anything to do why the loader

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T04:35:38+00:00Added an answer on June 17, 2026 at 4:35 am

    This happens because your form gets submitted, and so the page is reloaded. (you are seeing the page that the form direct you to)

    This is the normal browser behavior. You might want to try submitting your form with AJAX, if you need to remain on the current page..

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