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Home/ Questions/Q 4601222
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T23:47:40+00:00 2026-05-21T23:47:40+00:00

i have this json data {results:{ result:{ count:182, firsthit:1, lasthit:182, name:Primary Schools, schoolhit:[{ districtno:25,

  • 0

i have this json data

{"results":{
    "result":{
        "count":182,
        "firsthit":1,
        "lasthit":182,
        "name":"Primary Schools",
        "schoolhit":[{
            "districtno":25,
            "name":"ADMIRALTY PRIMARY SCHOOL",
            "precinct":"Woodlands",
            "region":"North",
            "zipcode":738907},
            {
            "districtno":27,
            "name":"AHMAD IBRAHIM PRIMARY SCHOOL",
            "precinct":"Yishun",
            "region":"North",
            "zipcode":768643},
            {
            "districtno":20,
            "name":"AI TONG SCHOOL",
            "precinct":"Sin Ming",
            "region":"North",
            "zipcode":579646},
            {
            "districtno":19,
            "name":"ANCHOR GREEN PRIMARY SCHOOL",
            "precinct":"Sengkang",
            "region":"North",
            "zipcode":544969}]
        }
    }
}

im still learning to understand… but could anyone point me on the right direction. I would like to achieve this using PHP the following…

<select>
<?php print "<option value=\"$districtno\">$name</option>";?><br />
</select>
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  1. Editorial Team
    Editorial Team
    2026-05-21T23:47:41+00:00Added an answer on May 21, 2026 at 11:47 pm

    Like this:

    $data = json_decode($json)->{'results'}->{'result'}->{'schoolhit'};
    
    foreach ($data as $school) {
        echo "<option value=" . $school->{'districtno'} . ">" . $school->{'name'} . "</option>";
    }
    

    Obviously adapt the output to your needs but given your json that should fill out the values you want.

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