Question

I have this kind of class and i would like to take variable outside(return i guess) so that i would be able to do stuff with it.

    class MyClass{

        private function MyPrivate(){
            $rows = 'SomeVar';
            echo $rows.' is echoed from inside';
            //return $rows;
            return $this->rows;
        }

        function Foo(){
            $this->MyPrivate();
            //$this->rows;
        }
    //return $rows;
    //return $this->rows;
    }

    $myclass = new MyClass;
    $myclass->Foo();

    //$myclass->rows;

    echo '<br />';

    echo $rows.'is echoed from outside';

Echoing variable inside the private function inside the class works, but echoing variable outside does not. Commented out code is what I tried to use to achieve wanted result. I did not make this class so I do not want to mess with it and change anything in it, because I fear it may mess things up.

this is my out put:

SomeVar is echoed from inside
is echoed from outside

As you can see in the second instance there is no SomeVar(variable) present. I am surprised it’s working though.
I am reading up on documentation and tutorials on the web for the past two days but this needs to be solved soon, that is why I posted. Please help. Thanks.

Answer 1

When you use the return statement, you should assign it to a variable. Also, you should have returned $rows, not $this->rows, since they’re actually different variables:

class MyClass{

    private function MyPrivate(){
        $rows = 'SomeVar';
        echo $rows.' is echoed from inside';
        return $rows;
    }

    function Foo(){
        return $this->MyPrivate();
    }
}

$myclass = new MyClass;
$rows = $myclass->Foo();

echo '<br />';

echo $rows.'is echoed from outside';