Question

I have this little code snippet, but it’s not really working right now. I always have the resource id#5 error. I searched in google for a few pointers but didn’t found mutch to pass this issue. Here my code

<?php
include 'load_db.php';

$var1 = $_POST["gender_1"];
$var2 = $_POST["gender_2"];
$var3 = $_POST["age"];

$sql = mysql_query("SELECT url FROM links WHERE gender ='".$var1."' AND gender1 ='".$var2."' AND age ='".$var3."'");

$result_1 = mysql_query($sql)
OR die("Error: $sql </br>".mysql_error());

echo $result_1;
?>

Error: Resource id #5

Answer 1

You are using twice mysql_query(), remove mysql_query() from $sql:

$var1 = mysql_real_escape_string($_POST["gender_1"]);
$var2 = mysql_real_escape_string($_POST["gender_2"]);
$var3 = mysql_real_escape_string($_POST["age"]);

$sql = "SELECT url FROM links WHERE gender ='".$var1."' AND gender1 ='".$var2."' AND age ='".$var3."'";
$result_1 = mysql_query($sql) OR die("Error: $sql </br>".mysql_error());

then loop in results:

while($row = mysql_fetch_array($result_1)){
    print_r($row);
}