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Home/ Questions/Q 6875723
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:23:21+00:00 2026-05-27T04:23:21+00:00

I have this little code to capture text between brackets: $string = ‘[title=my title]

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I have this little code to capture text between brackets:

$string = '[title=my title] http://bit.ly/gANFxi [maps:some cool place]';    
preg_match_all('/\[([^\]]*)\]/', $string, $matches);
print_($matches[0]);

What I get is the following:

    Array(
      [0] => [title=my title]
      [1] => [maps:some cool place]
    )

I want to make more restrictive to avoid “[some-not cool]” or “[another+stuff]”,
so I need to catch only [some:thing] and [some=thing].

How can I do it?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:23:22+00:00Added an answer on May 27, 2026 at 4:23 am

    This will catch everything that contains a ‘=’ or ‘:’ and ignore others:

    $string = '[title=my title] http://bit.ly/gANFxi [maps:some cool place] [some-not cool] or [another+stuff]';
    preg_match_all('/\\[([^\\]]*[\\=|\\:][^\\]]*)\\]/', $string, $matches);
    print_r($matches[0]);
    

    Does this do the trick? Or are there further requirements? That is, this return “[some stuff=some:thing]” but should it? (note both the multiple words and both ‘=’ and ‘:’).

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