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Home/ Questions/Q 6534683
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:16:48+00:00 2026-05-25T10:16:48+00:00

I have this loop that produces many elements with different positions: if ( $row[‘Type’]

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I have this loop that produces many elements with different positions:

if ( $row['Type'] == "house") { ?>
    <div class="itemW" style="margin-left: <?=$row['X']?>px; margin-top: <?=$row['Y']?>px;">
    Item
   </div> <? 
}       

I need to change all the divs left position, I’m trying this:

 var items = document.getElementsByClassName("itemW");
 items[0].style.left = land.width() / items[0].style.left * 100;

The problem is that items[0].style.left doesn’t get the position of the first div. Also I don’t know how to do it with all the divs.

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:16:49+00:00Added an answer on May 25, 2026 at 10:16 am

    You can get all elements with a particular class name with

    document.getElementsByClassName("classname");
    

    for anything but IE < 9 at least 😛

    Then it’s just a matter of looping through them like so

    var meh = document.getElementsByClassName("classname");
    for (var i = 0; i < meh.length; i++)
        meh[i].style.left = land.width() / items[0].style.left * 100 + "px"; // "px" is very important.
                                                                             // also this will only work
                                                                             // if you have first set the
                                                                             // element's style attribute.
    
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