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Home/ Questions/Q 8482333
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T19:47:55+00:00 2026-06-10T19:47:55+00:00

I have this macro from someone’s code: #define Q_DEF_PROTOTYPE( Type, Name ) Type (*Name)

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I have this macro from someone’s code:

#define Q_DEF_PROTOTYPE( Type, Name ) Type (*Name)

#define COPY_FP( pDest, pSrc ) (*((void**)(&(pDest)))) = ((void*)(pSrc))

#define LIB_QUERY(lib_handle, proc)  dlsym(lib_handle, proc)

#define Q_DEF_PROTOTYPE( Type, Name ) \
COPY_FP( p->Name, LIB_QUERY( g_library, STRINGIZE(FUNC(Name)) ) ); \
void dummy_##Name

Not sure, what “void dummy_##Name” does? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T19:47:56+00:00Added an answer on June 10, 2026 at 7:47 pm

    It replace the ##Name with the value of Name parameter as string.


    Q_DEF_PROTOTYPE(myType, objectName) => void dummy_objectName

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