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Home/ Questions/Q 7051983
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Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T03:19:44+00:00 2026-05-28T03:19:44+00:00

I have this method calling the below method , i am purposufully providing a

  • 0

I have this method calling the below method , i am purposufully providing a wrong port number for the URL to be connected .
But to my surprise , the exception produced is being caught in first Method catch block
Why it is not being handled inside the executeData Method’s catch block ??

**1st Method** 
public APIResponse execute(Request request, Class<? extends Response> responseClass) {
        try {
        String xmlResponse = executeData(request);
                  // some code
        return response;
        }
        catch (Exception ex) {

            return new Response(ErrorCode.SYSTEM_ERROR);
        }
    }

2nd Method
public String executeData(Request request) throws IOException {
        URL url = null;
        URLConnection urlc = null;
        try {
            url = new URL("http://localhost:80870/");
            urlc = url.openConnection();

        }
        catch (Exception ex) {
        ex.printStackTrace();
**// This is not being executed .**
        }

                           // Some code
                   // Some code
        return xmlResponse;
    }
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  1. Editorial Team
    Editorial Team
    2026-05-28T03:19:45+00:00Added an answer on May 28, 2026 at 3:19 am

    That’s probably because your line

    // some code
    

    produces another exception that is caught. Your 2nd method does not throw any exception, I see nothing wrong with that.

    connection.connect();
    

    Will throw the exception.

    You could also check for the status:

    int responseCode = connection.getResponseCode();
    if (responseCode != 200) {
        // Not OK.
    }
    
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