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Home/ Questions/Q 6815679
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:50:09+00:00 2026-05-26T20:50:09+00:00

I have this method . The issue is that when this condition is met

  • 0

I have this method .
The issue is that when this condition is met

if (bagList==null||bagList.size()<1 && UngarList==null||UngarList.size()<1 )

It is going into the catch block here

catch (Exception e) {

        this.errorText = e.getMessage().toString();
        info.setErrorText(this.errorText.toString());
        response.setinfo(info);

    }

But still it is execuing the next lines that is

final boolean toProceedorNot = validate(bagList.toArray(new Bag[bagList.size()]))

what is want is if this is met

if (bagList==null||bagList.size()<1 && UngarList==null||UngarList.size()<1 )
**then directly return the   response;**

This is my method

public Response getData(Request request) {

    Info info = new Info();

    Response response = new Response();
    String xmlrequest = request.getxmlMessage();

    HashMap listMap = new HashMap();
    List<Ungar> UngarList = new ArrayList<Ungar>();
    List<Bag> bagList = new ArrayList<Bag>();

    UniverseStaxParser xmlparser = new UniverseStaxParser();
    try {
        listMap = (HashMap) xmlparser.parseData(xmlrequest);

        UngarList = (List<Ungar>) listMap.get("UngarItems");

        bagList = (List<Bag>) listMap.get("bagItems");


        if (bagList==null||bagList.size()<1 && UngarList==null||UngarList.size()<1 )
            throw new Exception("No Valid Data is passed as Input ");

    } catch (Exception e) {

        this.errorText = e.getMessage().toString();
        info.setErrorText(this.errorText.toString());
        response.setinfo(info);

    }

    final boolean toProceedorNot = validate(bagList.toArray(new Bag[bagList.size()]));


    try {
        if (!toProceedorNot) {
            info.setErrorText(errorText);
            response.setinfo(info);

        } else {

            // some logic here goes 
        }
    } catch (Exception e) {
        errorText = e.getMessage().toString();
        info.setErrorText(errorText);
        response.setinfo(info);
    }



    return response;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:50:09+00:00Added an answer on May 26, 2026 at 8:50 pm

    Why wouldn’t it execute those lines? They’re outside the try/catch, and nothing prevents normal program execution flow.

    Unless you return from the method (or otherwise alter control flow) execution will continue at the statement following the catch block.

    Return the Response from the catch block if you want to return the response from the catch block.

    I’m not convinced that this is a great use of a general-purpose Exception, however.

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