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Home/ Questions/Q 7403899
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:10:37+00:00 2026-05-29T05:10:37+00:00

i have this model and configuration public class Person { public int? FatherId {

  • 0

i have this model and configuration

public class Person
 {
     public int? FatherId { get; set; }
     public virtual Person Father { get; set; }
     public int? MotherId { get; set; }
     public virtual Person Mother { get; set; }
     public virtual List<Person> Childs { get; set; }

 }
 class PersonConfiguration : EntityTypeConfiguration<Person>
 {
     public PersonConfiguration()
     {
         HasOptional(e => e.Father).WithMany(e => e.Childs)
              .HasForeignKey(e => e.FatherId);
         HasOptional(e => e.Mother).WithMany(e => e.Childs)
              .HasForeignKey(e => e.MotherId);
     }
 }

and i get this error where the type is initial.

Schema specified is not valid. Errors: (151,6) : error 0040: Type
Person_Father is not defined in namespace ExamModel (Alias=Self).

Is there a way to map Childs property by both properties (motherId and fatherId)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:10:38+00:00Added an answer on May 29, 2026 at 5:10 am

    Its not possible to map two navigational properties to a single collection property. It looks ridicules but you have to have two collection properties

    public class Person
     {
         public int? FatherId { get; set; }
         public virtual Person Father { get; set; }
         public int? MotherId { get; set; }
         public virtual Person Mother { get; set; }
         public virtual List<Person> ChildrenAsFather { get; set; }
         public virtual List<Person> ChildrenAsMother { get; set; }
     }
    
     class PersonConfiguration : EntityTypeConfiguration<Person>
     {
         public PersonConfiguration()
         {
             HasOptional(e => e.Father).WithMany(e => e.ChildrenAsFather)
                  .HasForeignKey(e => e.FatherId);
             HasOptional(e => e.Mother).WithMany(e => e.ChildrenAsMother)
                  .HasForeignKey(e => e.MotherId);
         }
     }
    
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