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Home/ Questions/Q 1044845
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:53:34+00:00 2026-05-16T15:53:34+00:00

I have this mysql query: UPDATE `table`.`wp_12_postmeta` SET `meta_value` = ‘yyy’ WHERE `wp_12_postmeta`.`meta_id` =5

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I have this mysql query:

UPDATE `table`.`wp_12_postmeta` 
   SET `meta_value` = 'yyy' 
 WHERE `wp_12_postmeta`.`meta_id` =5 
 LIMIT 1 ;

How do i incorporate this:

  • instead of wp_12_ i want a variable $prefix (variable holds wp_4_, wp_3_, etc)
  • instead of yyy i want a value $perf (variable is a name )
  • instead of 5 i want a value $meta_id (variable is a nr)

Thank u!

P.S.

here is what i use and it works:

$wpdb->query("UPDATE ".$prefix."postmeta SET meta_value = '".$perf."' WHERE meta_id = '".$meta_id."' LIMIT 1 "); 

Problem is, when i execute this query, severl post meta fields are updated, instead of just one.
Ty

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:53:35+00:00Added an answer on May 16, 2026 at 3:53 pm

    Here’s how I would write this with PDO:

    $prefix = "wp_4_";
    $sql = "UPDATE `table`.`{$prefix}postmeta` SET `meta_value` = ? 
      WHERE `{$prefix}postmeta`.`meta_id` = ? LIMIT 1";
    
    $stmt = $pdo->prepare($sql);
    $stmt->execute(array($perf, $meta_id));
    
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