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Home/ Questions/Q 9211487
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T01:18:29+00:00 2026-06-18T01:18:29+00:00

I have this NSArray: NSArray* temp=[[NSArray alloc] initWithObjects:@one,@five,@two,nil]; for(NSString* obj in temp){ NSLog(@current item:%@

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I have this NSArray:

NSArray* temp=[[NSArray alloc]
initWithObjects:@"one",@"five",@"two",nil];

for(NSString* obj in temp){ 
    NSLog(@"current item:%@ Next item is:%@",obj, ***blank***);
}

What needs to replace blank? Do I need to know the upcoming object?

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  1. Editorial Team
    Editorial Team
    2026-06-18T01:18:30+00:00Added an answer on June 18, 2026 at 1:18 am

    This only works if your objects are unique (i. e. there are no identical objects in the array):

    id nxt = nil;
    int nxtIdx = [temp indexOfObject:idx] + 1;
    if (nxtIdx < temp.count) {
        nxt = [temp objectAtIndex:nxtIdx];
    }
    NSLog(@"current item:%@ Next item is:%@", obj, nxt);
    

    But in my opinion, this is a hack. Why not use a normal for loop with the index of the object:

    for (int i = 0; i < temp.count; i++) {
        id obj = [temp objectAtIndex:i];
        id next = (i + 1 < temp.count) ? [temp objectAtIndex:i + 1] : nil;
    }
    

    Or (recommended) enumerate it using a block

    [temp enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
        id next = nil;
        if (idx + 1 < temp.count) {
            next = [temp objectAtIndex:idx + 1];
        }
    }];
    

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