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Home/ Questions/Q 4572434
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T19:38:44+00:00 2026-05-21T19:38:44+00:00

I have this paragraph: <p>FIRST SECOND THIRD</p> and I want to wrap the second

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I have this paragraph:

<p>FIRST SECOND THIRD</p>

and I want to wrap the second word in a SPAN like so:

<p>FIRST <span>SECOND</span> THIRD</p>

If I do this:

text.replace(/\s(\w+)\s/, '<span>$1</span>');

the space characters before and after the word disappear. Why? What am I doing wrong? I thought /\s(\w+)\s/ captures the word but not the spaces.

See here: http://jsfiddle.net/simevidas/TpTzV/

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  1. Editorial Team
    Editorial Team
    2026-05-21T19:38:45+00:00Added an answer on May 21, 2026 at 7:38 pm

    The spaces are stripped away because they’re part of the entire match. The capture is what it remembers to substitute back into the replacement string via backreferences.

    If JavaScript supported both lookahead and lookbehind assertions you could do this:

    text.replace(/(?<\s)(\w+)(?=\s)/, '<span>$1</span>');
    

    But it doesn’t, so you can try capturing the spaces (separately from the word you’re wrapping) and putting them back in instead:

    text.replace(/(\s)(\w+)(\s)/, '$1<span>$2</span>$3');
    
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