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Home/ Questions/Q 6706729
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:33:17+00:00 2026-05-26T07:33:17+00:00

i have this part of a code and i cant understund why the second

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i have this part of a code and i cant understund why the second loop inside the first does not work. I query two tables and i placed an echo inside the second table to see if it echo’s but it does not either . thanx in advance

while($row = mysql_fetch_array($result))
{
 echo "<li class=\"s01\"><a class=\"s03\" href=" . $row['link'] . "><span>". $row['onomaselidas'] ."</span></a>\n";
 echo "<ul class=\"pn2\">\n";
 $idd[]=$row['idwebsiteprimary'];
   while($row2 = mysql_fetch_array($result2))
   {
    echo "test";
   if($idd[$url]==$row2['idwebsite'])
    {
    echo "<li class=\"s01\"><a href=\"a\"><span>". $row2['name'] ."</span></a></li>\n";
    }
   }
 echo "</ul>\n";
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:33:18+00:00Added an answer on May 26, 2026 at 7:33 am

    After the first iteration of the first loop, the internal pointer of the second result set is at the end, so the second loop will not execute, because mysql_fetch_array() will return false immediately. If you want to it exactly as above – the second result set is not dependant on the first – you will need to do this:

    // First, get the results of set 2 into an array
    $resultset2 = array();
    while ($row = mysql_fetch_assoc($result2)) $resultset2[] = $row;
    
    while ($row = mysql_fetch_assoc($result)) { // Do your thang
      echo "<li class=\"s01\"><a class=\"s03\" href=" . $row['link'] . "><span>".$row['onomaselidas'] ."</span></a>\n";
      echo "<ul class=\"pn2\">\n";
      $idd[] = $row['idwebsiteprimary'];
      foreach ($resultset2 as $row2) { // Foreach sets it's pointer to the beginning every time, so this should work
        echo "test";
        if ($idd[$url]==$row2['idwebsite']) {
          echo "<li class=\"s01\"><a href=\"a\"><span>". $row2['name'] ."</span></a></li>\n";
        }
      }
      echo "</ul>\n";
    }
    

    Alternatively, you can reset the internal pointer of $result2 on each iteration of the first loop by calling mysql_data_seek($result2, 0); like this:

    while ($row = mysql_fetch_array($result)) {
      echo "<li class=\"s01\"><a class=\"s03\" href=" . $row['link'] . "><span>". $row['onomaselidas'] ."</span></a>\n";
      echo "<ul class=\"pn2\">\n";
      $idd[] = $row['idwebsiteprimary'];
      mysql_data_seek($result2, 0);
      while ($row2 = mysql_fetch_array($result2)) {
        echo "test";
        if($idd[$url]==$row2['idwebsite']) {
          echo "<li class=\"s01\"><a href=\"a\"><span>". $row2['name'] ."</span></a></li>\n";
        }
      }
      echo "</ul>\n";
    }
    
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