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Home/ Questions/Q 7915207
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T14:22:51+00:00 2026-06-03T14:22:51+00:00

I have this php function that has to perform some processing on a given

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I have this php function that has to perform some processing on a given array:

processArray($arrayToProcess) {

  $arrayToProcess['helloStackOverflow'] = TRUE;
}

Later, the code invokes the following:

$niceArray = array('key' => 'value');
processArray($niceArray);

The key ‘helloStackOverflow’ isn’t available outside the processArray function. I tried calling the following:

processArray(&$niceArray);

Using “&” helps, however it raises some warning:

Deprecated function: Call-time pass-by-reference has been deprecated; If you would like to pass it by reference, modify the declaration of populateForm_withTextfields()

Tried the & in there, but that just stops the code.

How should I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T14:22:54+00:00Added an answer on June 3, 2026 at 2:22 pm

    You have to define the reference in the function, not in the call to the function.

    function processArray(&$arrayToProcess) {
    
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