Question

I have this PHP script (test.php):

<?php

    $cmd = "/usr/bin/sass --watch file1.scss";

    system($cmd);

?>

Now I call my PHP script from CLI this way:

/usr/bin/php test.php

And I get no output (it should print SASS is watching for changes).

If I call the SASS command directly from the shell, it outputs correctly.

Why?

Info: I’m using the PHP 5.3.6 version on OS X Lion

Edit: Please, note that this command watches for changes, it seems to behave differently to a regular command.

Edit2: The command works, it compiles correctly. The only thing lacking is the output (I want to debug and see errors 🙂

Answer 1

Some command line utilities like sass, manipulate the output pipe in some way that PHP can’t use.

So, in this particular case, there is no solution.