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Home/ Questions/Q 8100877
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T22:51:15+00:00 2026-06-05T22:51:15+00:00

I have this piece of code: @Entity @Table(name = MOVERS) public class MOVers implements

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I have this piece of code:

@Entity
@Table(name = "MOVERS")
public class MOVers implements Serializable {
    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumns({
    @JoinColumn(name = "X1077_69_EDECESSOR", referencedColumnName = "CLASSID"),
    @JoinColumn(name = "X1077_70_EDECESSOR", referencedColumnName = "ID")})
    private MOVers predecessor;
}

The database should not have null values. If created version is the first then it should not have predecessor, and columns (X1077_69_EDECESSOR, X1077_70_EDECESSOR) should be equal to 0. I thought about creation of Dummy object for this reason, but it is not possible because some other columns must be unique.

How can I do it by using EclipseLink?

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  1. Editorial Team
    Editorial Team
    2026-06-05T22:51:16+00:00Added an answer on June 5, 2026 at 10:51 pm

    The database have no any foreign keys, and this DB is used in other application with persistence API that do not understand NULL fields. I solved this problem when I have added UPDATE statement, like this one, to the creation stage of the new object:

    SET X1077_69_EDECESSOR = 0, X1077_70_EDECESSOR = 0, WHERE ID = :moversid
    

    In this case new object creates with NULL fields and then they will be updated to 0 value.

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