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Home/ Questions/Q 5971145
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T20:28:33+00:00 2026-05-22T20:28:33+00:00

I have this piece of code which gives to SAXParseError i.e., it is not

  • 0

I have this piece of code which gives to SAXParseError i.e., it is not getting the content, but the same thing when i use in my test pg it works correctly. Here i am providing my original code piece, can any1 figure out what is the problem

This is the part where I fetch a xml and append a node to it but it seems that i am not able to get the file itself

String atemp=readFileAsString("../webapps/abc/include/xml/data.xml")

        log.info("ok thats good")

        String[] splitString=res.split(",")

        log.info(atemp)

        try
        {
            def root = new XmlSlurper().parseText(atemp)
        }
        catch(Exception e)
        {
            log.debug("parse errror: "+e)
        }
        root.appendNode {
          row {
            name(splitString[1])
            host(splitString[2])
            desc(splitString[3])
            product(splitString[4])
            type(splitString[5])
            time(splitString[6])
            by(splitString[7])
          }
        }

        def outputBuilder = new StreamingMarkupBuilder()
        String temp = outputBuilder.bind{ mkp.yield root }

        File file = new File("../webapps/abc/include/xml/data.xml");
        BufferedWriter output = new BufferedWriter(new FileWriter(file));
        output.write(temp);
        output.close();
        log.info(temp)

my readFileAsString function

private String readFileAsString(String filePath) {
    try
    {
        StringBuffer fileData = new StringBuffer();
        BufferedReader reader = new BufferedReader(new FileReader(filePath));
        log.info(reader==null);
        char[] buf = new char[1024];
        int numRead=0;
        while((numRead=reader.read(buf)) != -1){
            String readData = String.valueOf(buf, 0, numRead);
            fileData.append(readData);
            log.info(readData)
        }
        reader.close();
        log.info("File Content\n"+fileData.toString());
        return fileData.toString();
    }
    catch (Exception e) 
    {
        log.info(e);
    }
}

Output

INFO http-5050-Processor24 com.abc.helper.WriteXml - false
INFO http-5050-Processor24 com.abc.helper.WriteXml - File Content
INFO http-5050-Processor24 com.abc.helper.WriteXml - ok thats good

Note: I am able to open the file in my test program with the same path

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T20:28:34+00:00Added an answer on May 22, 2026 at 8:28 pm

    Assuming this is in Groovy, I believe you can replace all of your code with:

    File f = new File( '../webapps/abc/include/xml/data.xml' )
    def root = new XmlSlurper().parse( f )
    String[] splitString = res.split( ',' )
    root.appendNode {
      row {
        name(splitString[1])
        host(splitString[2])
        desc(splitString[3])
        product(splitString[4])
        type(splitString[5])
        time(splitString[6])
        by(splitString[7])
      }
    }
    def outputBuilder = new StreamingMarkupBuilder()
    String newXml = outputBuilder.bind{ mkp.yield root }
    f.text = newXml
    

    But I repeat, doing this inside a web application is probably a bad idea as if two threads call this code at the same time, the file is going to be unpredictable (and get more unpredictable as it gets larger)

    Also, you might want to change:

    File f = new File( '../webapps/abc/include/xml/data.xml' )
    

    to

    File f = new File( "${System.properties['catalina.base']}/webapps/abc/include/xml/data.xml" )
    

    As suggested to you in a previous question of yours

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