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Home/ Questions/Q 6607919
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:33:17+00:00 2026-05-25T19:33:17+00:00

i have this piece of code which i use to add some elements: string

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i have this piece of code which i use to add some elements:

  string xmlTarget = string.Format(@"<target name='{0}' type='{1}' layout='${{2}}'  />",
                                                new object[] { target.Name, target.Type, target.Layout });
            Configuration configuration = ConfigurationManager.OpenExeConfiguration(ConfigurationUserLevel.None);
            var xmlDoc = XElement.Load(configuration.FilePath);
            var nlog = xmlDoc.Elements("nlog");

            if (nlog.Count() == 0)
            {
                return false;
            }
            xmlDoc.Elements("nlog").First().Elements("targets").First().Add(xmlTarget);
            xmlDoc.Save(configuration.FilePath,SaveOptions.DisableFormatting);
            configuration.Save(ConfigurationSaveMode.Modified);
            ConfigurationManager.RefreshSection("nlog");
            return true;

it supposed to add a target to the xml , problem is it replace “<” with “&lt;” and “>” with “&gt;” which mess up my xml file.

how do i fix this ?

Note please dont pay attention to nlog, i`m concerned about the linqtoxml problem.

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:33:17+00:00Added an answer on May 25, 2026 at 7:33 pm

    You’re currently adding a string. That will be added as content. If you want to add an element, you should parse it as such first:

    XElement element = XElement.Parse(xmlTarget);
    

    Or preferrably, construct it instead:

    XElement element = new XElement("target",
        new XAttribute("type", target.Name),
        new XAttribute("type", target.Type),
        // It's not clear what your format string was trying to achieve here
        new XAttribute("layout", target.Layout));
    

    Basically, if you find yourself using string manipulation to create XML and then parse it, you’re doing it wrong. Use the API itself to construct XML-based objects.

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