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Home/ Questions/Q 983243
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:49:29+00:00 2026-05-16T04:49:29+00:00

I have this preprocessor directive: #define INDEXES_PER_SECTOR BYTES_PER_SECTOR / 4 where BYTES_PER_SECTOR is declared

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I have this preprocessor directive:

#define INDEXES_PER_SECTOR BYTES_PER_SECTOR / 4

where BYTES_PER_SECTOR is declared in another header file as:

#define BYTES_PER_SECTOR    64

I have this simple math equation that I wrote where after executing I get an assertion error as the value assigned to iTotalSingleIndexes is incorrect.

int iTotalSingleIndexes = (iDataBlocks - 29) / INDEXES_PER_SECTOR;

Now I believe this to be because of the preprocessor directive INDEXES_PER_SECTOR. Upon executing my equation iDataBlocks is 285 which is correct. I have confirmed this with gdb. The problem is that the value that gets assigned to iTotalSingleIndexes is 1 when it ought to be 16. I really have no idea why this is happening.

When I do something like:

int iIndexesInASector = INDEXES_PER_SECTOR;
int iTotalSingleIndexes = (iDataBlocks - 29) / iIndexesInASector;

the correct value gets assigned to iTotalSingleIndexes.

On other notes I use preprocessor directives in other equations and they work just fine so I am even more puzzled.

Any help would be much appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:49:30+00:00Added an answer on May 16, 2026 at 4:49 am

    The preprocessor simply performs token replacement – it doesn’t evaluate expressions. So your line:

    int iTotalSingleIndexes = (iDataBlocks - 29) / INDEXES_PER_SECTOR;
    

    expands to this sequence of tokens:

    int iTotalSingleIndexes = ( iDataBlocks - 29 ) / 64 / 4 ;
    

    …which, due to the associativity of the / operator, is then parsed by the compiler as:

    int iTotalSingleIndexes = ((iDataBlocks - 29) / 64) / 4;
    

    …which results in the value of 1. As leppie says, you want:

    #define INDEXES_PER_SECTOR (BYTES_PER_SECTOR / 4)
    

    This makes INDEXES_PER_SECTOR expand to a complete subexpression.

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