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Home/ Questions/Q 8750187
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:49:26+00:00 2026-06-13T12:49:26+00:00

I have this prettify html <a href=somepath> Text1 </a> <span> | </span> <a href=somepath>

  • 0

I have this prettify html

         <a href="somepath">
          Text1
         </a>
         <span>
          |
         </span>
         <a href="somepath">
          Text2
         </a>
         <span>
          |
         </span>
         <a href="somepath">
          Text3
         </a>

I used this code:

cnta= len(res.findAll('a'))-1 //I used -1 because I have one extra a tag
cnt = 0
while cnt<cnta:
    res2 = res.find('a').text
    cnt+=1
    print res2

I want to take all 3 Texts but the result is 3 times “Text1″… I know that I not saying anyone to go to next but I don’t know how to do it

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T12:49:27+00:00Added an answer on June 13, 2026 at 12:49 pm

    Just loop directly over the findAll results:

    for elem in res.findAll('a'):
        print elem
    

    The .find() method just returns the first element within res it finds, it doesn’t continue the search from the last hit you found. So on each run through the loop it’ll find the same element.

    If you want to limit the number of results, use slice notation:

    for elem in res.findAll('a')[:3]:
        print elem
    
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