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Home/ Questions/Q 7882705
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:20:51+00:00 2026-06-03T04:20:51+00:00

I have this pretty simple code: $start_date = new DateTime($post[‘start_date’]); $end_date = $start_date->add(new DateInterval(‘P6M’));

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I have this pretty simple code:

$start_date = new DateTime($post['start_date']);
$end_date = $start_date->add(new DateInterval('P6M'));
echo $start_date->getTimestamp(); // 1351836000
echo $end_date->getTimestamp(); // 1351836000

Of course, both end up as the same timestamp because adding the date interval affects the original $start_date. So how do I go about this so I can keep the original $start_date yet add 6 months to it in another variable?

I tried this with no luck:

$start_date = new DateTime($post['start_date']);
$start_date_actual = $start_date;
$end_date = $start_date_actual->add(new DateInterval('P6M'))->getTimestamp();
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  1. Editorial Team
    Editorial Team
    2026-06-03T04:20:52+00:00Added an answer on June 3, 2026 at 4:20 am

    Variables hold references to objects, not the objects themselves. So assignment just gets you more variables pointing to the same object, not multiple copies of the object.

    If you want a copy, use the clone keyword:

    $end_date = clone $start_date;
    $end_date->add(new DateInterval('P6M'));
    
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