Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8928085
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T08:21:31+00:00 2026-06-15T08:21:31+00:00

I have this problem. I use spring and I store the attached file (doc,pdf,png…)

  • 0

I have this problem.
I use spring and I store the attached file (doc,pdf,png…) into the server file system.
Then I save the path and name of the file into my db.
Now how can I read this file as a link into the browser?

I thought to write the file into a web position and give this location to the browser.
is it a good practice?
But how can I delete the file after visualization?

I hope the question is clear.

enter image description here

to write I use:

 /** what write for reach temp-file folder (my project name is intranet)
   I thougth TEMP_FOLDER=""/intranet/resources/temp-files/";
   but It doesnt work. ioexception (The system cannot find the path specified)
 */
 final static String TEMP_FOLDER=?????

public static String createTempFile(String originalPathFile,String fileName){
String tempPathFile="";
try {
    InputStream inputStream = new FileInputStream(originalPathFile);
    tempPathFile=TEMP_FOLDER+fileName;
    File tempFile = new File(tempPathFile);

    OutputStream out = new FileOutputStream(tempFile);
    int read = 0;
    byte[] bytes = new byte[1024];
    while ((read = inputStream.read(bytes)) != -1) {
        out.write(bytes, 0, read);
    }
    out.flush();
    out.close();
} catch (IOException ioe) {
     System.out.println("Error while Creating File in Java" + ioe);
}

return tempPathFile;
  }
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T08:21:32+00:00Added an answer on June 15, 2026 at 8:21 am

    Now how can I read this file as a link into the browser?

    Place the following link in your JSP

    <a href="<c:url value="/fileDownloadController/downloadFile?filename=xyz.txt"/>" title="Download xyz.txt"></a>
    

    In your controller:

    @Controller
    @RequestMapping("/fileDownloadController")
    public class FileDownloadController
    {
        @RequestMapping("/downloadFile")
        public void downloadFile( 
            @RequestParam String filename,
            HttpServletResponse response)
        {
            OutputStream outputStream = null;
            InputStream in = null;
            try {
                in = new FileInputStream("/tmp/" + filename); // I assume files are at /tmp
                byte[] buffer = new byte[1024];
                int bytesRead = 0;
                response.setHeader(
                    "Content-Disposition",
                    "attachment;filename=\"" + filename + "\"");
                outputStream = response.getOutputStream();
                while( 0 < ( bytesRead = in.read( buffer ) ) )
                {
                    outputStream.write( buffer, 0, bytesRead );
                }
            }
            finally
            {
                if ( null != in )
                {
                    in.close();
                }
            }
    
        }
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I become use raw socket and i have this problem: bad file descriptor the
Ok I have this problem I'm trying to use Jquery to load a partial
i am having this problem try to use the cocos2d CCScrollLayer I have added
i have problem use link_to_remote link_to_remote document example say link_to_remote Delete this post, :update
I'm having a misunderstanding problem with this use of Linq Query I do have
I have some problem with this mongoid. It's my first time to use mongoDB,
I have a problem. I want to use a LINQ query against this database:
I have this problem: I want to generate a new source code file from
How would you tackle this problem: I have data in my data store. Each
I have this problem: $id is id for each user $img = 'http://www.somesite.com/pictures/'; $no_img

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.