Question

I have this program :

int r = 4;//number add to d
int n = 3;//number of 0 add after 25
BigDecimal d = BigDecimal.valueOf(0.0025);

finaly i want to generate number : 0.0025004 and this number is generated by:
add n position after d then my number was : 0.0025000 and finaly add 0.000004 to my number 4 is r.

I know there are a several ways to do, but i want to avoid loop and use a maximum fonctinnality of BigDecimal

Answer 1

try it:

int r = 4;// number add to d
int n = 3;// number of 0 add after 25
BigDecimal d = BigDecimal.valueOf(0.0025);
double f  = r / Math.pow(10, d.scale() + n);
System.out.println(d.add(BigDecimal.valueOf(f)));

I hope this is useful