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Home/ Questions/Q 8886575
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:35:27+00:00 2026-06-14T21:35:27+00:00

I have this program, something related with statistic. maximo = max(muestra); minimo = min(muestra);

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I have this program, something related with statistic.

maximo = max(muestra);
minimo = min(muestra);
rango = maximo - minimo;
num_intervalo = round(1 + 3.322*log(length(muestra)));
amplitud = rango/num_intervalo;

rango_intervalo = [];
for i=1 : num_intervalo + 1
    if i == 1
        rango_intervalo(i: num_intervalo + 1) = minimo;
    else
        rango_intervalo(i: num_intervalo + 1) = rango_tabulado(i) + amplitud;
    end
    if i == num_intervalo + 1
        rango_intervalo(i: num_intervalo + 1) = maximo;
    end
end
rango_intervalo = rango_intervalo';

the intention is to create nine (or k intervals) intervals, where each interval has it ranges:

[1.580 - 2.587]
[2.587 - 3.594]
.
.
[9.636 - 10.650]

With code that I’ve programmed, it is resulting in 10 data not nine as per the intention.
Any idea, the improve this code?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:35:29+00:00Added an answer on June 14, 2026 at 9:35 pm

    How about:

    intervals = linspace(minimo, maximo, num_intervalo + 1 );
    intervals = [ intervals(1:end-1); intervals(2:end) ]';
    
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